Lösungen

5.1 2b)

`y=1/2 x^2 + 1; D_f=RR_0^(-) => W_f=[1,oo]`
`x=1/2 y^2 + 1`
`x-1=1/2 y^2`
`2x - 2 = y^2`
`y = sqrt(2x - 2)`
`D_(f^(-1))=[1,oo]; W_(f^(-1))=RR_0^(+)`

5.1 2c)

`y=(x-1)^2; D_f = [1;+oo] => W_f = RR_0^(+)` `x=(y-1)^2`
`sqrt x = y-1`
`sqrt x + 1 = y`
`D_(f^(-1))=RR; W_(f^(-1))=[1;oo]`