| UHU-Startseite►Mathematik►Jahrgangsstufen►9►Weiterentwicklung der Zahlvorstellung►Umgehen mit einfachen Wurzeltermen►(Lösungen)► |
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1.3
h) `sqrt (2^3*5^2*7^3) = sqrt (2^2*5^2*7^2*2*7) = 2*5*7*sqrt(2*7) = 70 sqrt 14`
` = 3*3 sqrt 2 * sqrt 10 + 3*3 sqrt 2 * sqrt 2 - 4 sqrt 10 * sqrt 10 - 4 sqrt 10*sqrt 2 = 3*3*2 *sqrt 5 + 3*3*2 - 4*10-4*2*sqrt 5 ` `= 18 sqrt 5 + 18 - 40 - 8 sqrt 5 = 10 sqrt 5 - 22` b) `(2 sqrt 72 - 3 sqrt 18 + 5 sqrt 8)*3*sqrt 10 = (2*2*3*sqrt 2 - 3*3 sqrt 2 + 5*2 sqrt 2)*3*sqrt 10` ` = (12 sqrt 2 - 9 sqrt 2 + 10 sqrt 2)*3*sqrt 10 = (13 sqrt 2)*3*sqrt 10 = 39*2*sqrt 5 = 78 sqrt 5` c) `(1 + sqrt 2 - sqrt 3)(1 - sqrt 2)-(1- sqrt 2 + sqrt 3)(1-sqrt 3)= (1 + sqrt 2 - sqrt 3 - sqrt 2 - sqrt 2*sqrt 2 + sqrt 3 * sqrt 2) - (1 - sqrt 2 + sqrt 3 - sqrt 3 + sqrt 2*sqrt 3 - sqrt 3*sqrt 3)` ` = (1 - sqrt 3 + 2 + sqrt 6) - (1 - sqrt 2 + sqrt 6 - 3) = 3 -sqrt 3 + sqrt 6 + 2 + sqrt 2 - sqrt 6 = 5 - sqrt 3 + sqrt 2`
b) `sqrt (a/(3b)) : sqrt(b^3/(27a)) = sqrt ((a*27 a)/(3 b*b^3)) = (3 a)/b^2` c) `sqrt b + b sqrt b + b^2 sqrt b = (1 + b+ b^2) sqrt b`
c) `1/3 sqrt 6 ` d) `sqrt 5 ` e) `1/2 sqrt 5`
b) `sqrt (1-r)^2 = |1-r|` c) `9 |r|`
b) `(sqrt 3 + sqrt 108)^2 = (sqrt 3)^2 + 2 sqrt 3 * sqrt 108 + (sqrt 108)^2 = 3 + sqrt (2 * 2 * 3 * 3 * 3 * 3) + 108 = 3 + 2*9 + 108 = 129` c) `((5 - sqrt 2)(5 + sqrt 2))/((sqrt 2 - sqrt 18)^2) = (25 - 2)/(2 - 2 sqrt 36 + 18) = 23/2`
b) `(sqrt x + sqrt y)/sqrt(xy) = (sqrt(xy)*sqrt(x+y))/(sqrt(xy)*sqrt(xy)) = sqrt(xy*(x+y))/xy` c) `sqrt x/sqrt y - (x -xy)/sqrt(xy) = (sqrt x*sqrt x)/(sqrt x * sqrt y)- (x -xy)/sqrt(xy) = (x - x + xy)/sqrt (xy) = (xy)/sqrt (xy) = (sqrt(xy)*sqrt(xy))/sqrt (xy) = sqrt(xy)` |